When you visit the set of a massive blockbuster that still has 16 months before it reaches movie theaters, the last thing you expect to see is footage. But that's exactly what Zack Snyder treated us to when a group of journalists visited the London set of next year's Justice League movie. We saw a finished scene -- well, a mostly finished scene -- that showed us exactly how two crucial Justice League members would meet.
The following contains massive spoilers for Justice League! Do not read any further if you do not want to know any details.
The scene in question shows how Bruce Wayne (Ben Affleck) recruits Barry Allen (Ezra Miller) for his mission. As we learned, at the end of Batman v Superman: Dawn of Justice, Superman's death has inspired Batman to band together the metahumans and prepare for a larger threat that the Dark Knight can sense is coming. The scene that Zack Snyder shows us plays out as such:
The scene tells us a number of very important things about Justice League. Obviously, it will be Bruce Wayne making the rounds to convince the metahumans that they need to join him in this fight against the mounting threat of Steppenwolf. Batman already has Wonder Woman on his side, but with Superman in a shallow grave, the Caped Crusader is going to need help. But the scene also shows us how quickly the recruitment process may take, which is refreshing because it suggests that Justice League won't have to waste an hour following Batman around as he tries to convince people we KNOW are going to join him anyway to sign on the dotted line.
The scene also tells us that this version of Barry, at the time that we are meeting him, is a loner in need of friends. That's a direct contrast to Team Flash on The CW. No Iris (yet). No teammates from S.T.A.R. Labs. Barry needs friends. And he's going to get them. Super Friends, even. We can't wait.
Your Daily Blend of Entertainment News
Thank you for signing up to CinemaBlend. You will receive a verification email shortly.
There was a problem. Please refresh the page and try again.